The probability of making a royal flush is 4/C(52,5) which is equivalent to 1/649740. In terms of odds, this is 649739 to 1 Either you interpreted it wrong, or they were slightly off. Wow.that is much smaller.

- Straight flush hands that differ by suit alone, such as 7 ♦ 6 ♦ 5 ♦ 4 ♦ 3 ♦ and 7 ♠ 6 ♠ 5 ♠ 4 ♠ 3 ♠, are of equal rank. An ace-high straight flush, such as A ♦ K ♦ Q ♦ J ♦ 10 ♦, is called a royal flush or royal straight flush and is the best possible hand in high games when not using wild cards.
- Aces can be high or low. An ace-high straight flush is called a royal flush, the best possible hand in poker. ♣ Betting Variations. Texas Hold'em can be played in three basic variations: Limit Hold'em: In Limit Hold'em, the amount you can bet or raise is fixed, according to the posted stakes. A bet placed before the turn card (4th community.

**Farley**

I am trying to determine the probability of the following occurrences in a Texas Holdem Game with 9 players.

On the flop:

Royal Flush versus queen high straight flush ( I.E board of 10 J Q suited versus AK and 89 of same suit)

On the turn:

Flopped Royal Flush versus 4 of a kind made on the turn

Flopped 4 of a kind versus turned 4 of a kind (pocket pair versus pocket pair)

On the flop:

Royal Flush versus queen high straight flush ( I.E board of 10 J Q suited versus AK and 89 of same suit)

On the turn:

Flopped Royal Flush versus 4 of a kind made on the turn

Flopped 4 of a kind versus turned 4 of a kind (pocket pair versus pocket pair)

**ThatDonGuy**

I am trying to determine the probability of the following occurrences in a Texas Holdem Game with 9 players.

On the flop:

Royal Flush versus queen high straight flush ( I.E board of 10 J Q suited versus AK and 89 of same suit)

There are combin(52,3) = 22,100 different flops, of which four (one of each suit) is Q-J-10, so the probability of the three flop cards being Q-J-10 suited is 1/5525.

I'm not 100% sure I am calculating this right, but here goes...

The probability that any of the 18 hole cards is the Ace of that suit is 18/49.

The probability that that player's other card is the King is 1/48.

The probability that any of the 16 remaining hole cards is the 9 of that suit is 16/47.

The probability that that player's other card is the 8 is 1/46.

The probability that one player in a nine-player game has a royal on the flop and another has a Queen-high SF is the product of these five numbers, or about 1 in 97,551,242.

**MaxPen**

Where did this happen at?

**Farley**

Where did this happen at?

It didnt, just trying to determine the probabilities for promotional purposes.

**Ibeatyouraces**

I've seen a straight flush vs. straight flush bad beat jackpot once.

**Farley**

I've seen a straight flush vs. straight flush bad beat jackpot once.

Flopped?<---very uncommon, hence my inquiry in my first post.

I like to know the probability of that as well (IE and three suited connect cards with each player holding the two straight flush cards for either side.)

with all 5 board cards, ive seen straight flush versus straight flush (each player using both hole cards) quite a few times in 25 years or so in card rooms

**MaxPen**

It didnt, just trying to determine the probabilities for promotional purposes.

There is a point in time that an outcome is so unlikely that a promotion based on it is BS.

**Farley**

There is a point in time that an outcome is so unlikely that a promotion based on it is BS.

I agree, players would recognize that point and it would likely have little affect. Trying to find the median.

Currently the Bad Beat is AAA1010 or better losing to 4 of a kind or better, both cards must play.

### Royal Straight Flush Probability Texas Holdem Tournaments

Objective:To add additional value to the jackpot ( I.E adding 5K 10K 15K ...or up to 50 or 100K) depending on the hands that qualify and when those hands are made.

**AlmondBread**

about 1 in 97,551,242.

I agree.4 * C(9,2) / C(52,7) / C(7,3) / 3!!